Complex entanglement between pointer and array

#include<stdio.h>
#include<windows.h>
int main()
{   
    char str[] = "I love you";
    char *target = str;

    int count = 0;
    while (*target++ !='\0')
    {   
        count++;
        /* code */
       // printf("%d",count);
    }
    printf("the total is :%d",count);

    system("pause");
}

#include<stdio.h>
#include<windows.h>
int main(){
    int array[2][3] = {0};
    for(int i =0;i<2;i++){
        for(int j=0;j<3;j++){
            scanf("%d",&array[i][j]);

        }


    }
    printf("size of int is %d\n",sizeof(int));
    printf("the add of array pointed is %d\n",array);// Let's print out the address according to the decimal system , Is the first address of the entire array 
    printf("the value of *array pointed is %d\n",*array);// It can be considered to get the address of the nested one-dimensional array 
    printf("the value of **array is %d\n",**array);// You can think of getting the value of a one-dimensional array 
    printf("the value of *(array+1) pointed is %d\n",*(array+1));
  
    printf("the add of array+1 pointed is %d\n",array+1);
    system("pause");
    /*
     After output and printing, it can be obtained through analysis ,array Is a pointer to five arrays containing elements 
    */
}
/*
 How to understand two-dimensional arrays ？ Two dimensional arrays are stored in memory according to one-dimensional arrays . It can be considered as nested .
*/

#include<stdio.h>
#include<windows.h>
int main()
{   // The following is a pointer array 
    char *p1[5] = {
        "every one can dream!",
        "i think i can successful",
        "dont care it ,just do it for your dream",
        "how are you",
        "believe yourself"
};
    for (int i =0;i<5;i++){
        printf("%s\n",p1[i]);
    }
    system("pause");

}

// Here is an example of an array pointer , Pointer to array , Don't think it points to an address , Instead, it points to the entire array 
#include<stdio.h>
#include<windows.h>
int main() 
{
    int temp[] ={1,2,3,4,5};
    
    int (*p2)[5] = &temp;
    int i;
    for(i =0;i<5;i++)
    {
        printf("%d\n",*(*p2+i));

    }
    system("pause");
}

/* Use the pointer method to save the maximum value to the variable a In the middle , The minimum value is saved to the variable b In the middle */
#include <stdio.h>

void ff(int *p1, int *p2) {// The process of passing the address content of the argument to the past assignment 
	int a;// and main Function a Not the same 
	a = *p1;// take p1 The value on the address is passed to a;
//	printf("%d", &a);
	*p1 = *p2;
	*p2 = a;
}



int main() {
	int a, b;
	int *p_1, *p_2; // Define pointer type variables to point to int Variable of type 
	scanf("%d %d", &a, &b);
	p_1 = &a; // Attach an address to p_1,p_2;
	p_2 = &b;
	printf("%d,%d\n", &a, &b);
	if (a < b) {
		ff(p_1, p_2);
	}
	printf(" The maximum value is %d, The minimum value is %d", a, b);
	return 0;
}

#include<stdio.h>
#include<windows.h>
int main()
{   // Initialize the two pointers and start pointing to null 
    int *p1 =NULL;
    int *p2 =NULL;
    int *p3 =NULL;
    int a =6,b =8,c =10;
    p1 =&a;// representative p1 Pointer to a The address of 
    p2 =&b;
    p3 =&c;
    // You can print *p1/*p2 What does it stand for , In fact, I'll take it again this time * Words , And pointer defined * Dissimilarity , Indicates that the fetch pointer points to the content at the address 
    // eg:
    printf("the value of a is %d\n",*p1);
    printf("the address of a is %p\n",p1);// Print the address directly %p

    // The exchange value can be directly exchanged 
    // eg:
    *p1 = *p2;
    printf("this time ,the value of a is %d\n",a);
   
    //? Try address swapping ？
    p1 = p3;
    printf("the value of a is %d\n",a);// Print out and you will only find that value exchange is effective , Using a pointer is just a change in the direction of the pointer 
    printf("the value of pointer p1 is %d",*p1);
    system("pause");
}

#include<stdio.h>
#include<windows.h>
int main(){
    int array[2][3] = {0};
    for(int i =0;i<2;i++){
        for(int j=0;j<3;j++){
            scanf("%d",&array[i][j]);

        }


    }
    printf("size of int is %d\n",sizeof(int));
    printf("the add of array pointed is %d\n",array);// Let's print out the address according to the decimal system , Is the first address of the entire array 
    printf("the value of *array pointed is %d\n",*array);// It can be considered to get the address of the nested one-dimensional array 
    printf("the value of **array is %d\n",**array);// You can think of getting the value of a one-dimensional array 
    printf("the value of *(array+1) pointed is %d\n",*(array+1));
  
    printf("the add of array+1 pointed is %d\n",array+1);
    system("pause");
    /*
     After output and printing, it can be obtained through analysis ,array Is a pointer to five arrays containing elements 
    */
}
/*
 How to understand two-dimensional arrays ？ Two dimensional arrays are stored in memory according to one-dimensional arrays . It can be considered as nested .
*/

#include<stdio.h>
#include<windows.h>
// Pointer array 
int main()
{

    char *cBooks[] = 
    {
        "Cease to struggle and you cease to live",
        "Time ca heal a broken heart,but it can also break a waiting heart",
        "the fox changes his skin but not his habbits",
        "Time is but a river flowing from our past"

    };
    char **jgdabc;
    char **jgdabc_loves[4];
    jgdabc_loves[0] = &cBooks[0];
    jgdabc_loves[1]  = &cBooks[1];
    jgdabc_loves[2] = &cBooks[2];
    jgdabc_loves[3] = &cBooks[3];
    printf("%d\n",jgdabc_loves[0]);
    printf("%d\n",*jgdabc_loves);
    printf("%s\n",*jgdabc_loves[0]);
    printf("%c\n",**jgdabc_loves[0]);
    printf("%c\n",**jgdabc_loves[1]);
    system("pause");

}