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【7.12】Codeforces Round #806 (Div. 4)
2022-07-19 13:40:00 【ZhgDgE】
E. Mirror Grid
The question : Given 01 matrix , One operation can reverse one grid . Ask how many operations at least make the rotation of the matrix equal to the original matrix any time .
Ideas : A formula of rotation is summarized : If a certain point ( i , j ) (i,j) (i,j) stay n × n n\times n n×n Rotate in the matrix of 90 ° 90° 90° , Then the coordinates are ( j , n − i + 1 ) (j,n-i+1) (j,n−i+1) . Pay attention to this question n n n You can't enumerate too many when it's an odd number .
AC Code :https://codeforces.com/contest/1703/submission/163868674
G. Good Key, Bad Key
The question : existing n n n A box , The first i i i There are a i a_i ai Gold coin . Now you have to press 1 1 1 To n n n Open these boxes in order . You can open the box with two kinds of keys , There are good keys and bad keys . Each time you use a good key to unpack, it will cost k k k Gold coins ; Each time you use a bad key to unpack, you won't spend gold coins , But it will halve the gold coins in all unopened boxes, including the box to be opened ( Round down ). first , You don't have any gold coins or keys . During unpacking , You can be in debt . Ask how many gold coins you can hold at most after opening all the boxes .
Answer key :Codeforces Round #806 (Div. 4)
Ideas : greedy . If we choose x x x A bad key , that 1 Analysis shows that the bad key must be the last and continuous use . So enumerate the boundaries of good keys and bad keys , Just update the answer .
AC Code :https://codeforces.com/contest/1703/submission/164017522
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