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Addition and subtraction of busybox date time

2022-07-19 06:09:00 【xp5xp6】

1、 Download and install busybox：

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wget http://busybox.net/downloads/busybox-1.29.3.tar.bz2

tar -jxvf busybox-1.29.3.tar.bz2

cd busybox-1.29.3

make defconfig // If the size of the root file system is not very demanding , You can use it directly busybox Default configuration

make

make install

structure date link

ln -sf ./busybox ./date

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busybox date Parameters,

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[busybox-1.29.3]# ./date --help
BusyBox v1.29.3 (2019-11-25 11:00:35 CST) multi-call binary.

Usage: date [OPTIONS] [+FMT] [TIME]

Display time (using +FMT), or set time

[-s,--set] TIME    Set time to TIME
-u,--utc    Work in UTC (don't convert to local time)
-R,--rfc-2822    Output RFC-2822 compliant date string
-I[SPEC]    Output ISO-8601 compliant date string
        SPEC='date' (default) for date only,
        'hours', 'minutes', or 'seconds' for date and
        time to the indicated precision
-r,--reference FILE    Display last modification time of FILE
-d,--date TIME    Display TIME, not 'now'
-D FMT        Use FMT for -d TIME conversion

Recognized TIME formats:
hh:mm[:ss]
[YYYY.]MM.DD-hh:mm[:ss]
YYYY-MM-DD hh:mm[:ss]
[[[[[YY]YY]MM]DD]hh]mm[.ss]
‘date TIME’ form accepts MMDDhhmm[[YY]YY][.ss] instead
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Linux In the system date Generally, you can directly subtract dates ,

for example ： centos7 System

date Get the time of the day before ： date -d -1day perhaps date -d ‘1 day ago’

date Get the time of the previous month ： date -d ‘1 month ago’

date Get the time of the previous year ： date -d ‘1 year ago’

and busybox date You can't get the time of the previous day directly ,, You need the method of subtracting time numbers to obtain the time of the previous day

for example ： busybox date Get the time of the day before ：

Considering that the current time is the first day of the year 1 month 1 What happened in Japan , The code is as follows ：

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year=date +%Y // Get the year of the current time
month=date +%m // Get the month of the current time
day=date +%d // Get the date of the current time

if [[ “ $d a y " = = " 01 "]]; t h e n / / Such as fruit When front when between yes 1 Number, be Examination Consideration One Next month Share ask topic i f [["$ month” == “01” ]];then // If the current time is 1 month 1 Number ,, The day before the acquisition is the last day of last year , So the year needs to be reduced by one , The month and date are 12 month 31 Japan
year=expr $year - 1
yesterday=“ ${year}-12-31" elif [[ "$ month” == “03” ]];then // If the current time is 3 month 1 Number , The day before the acquisition is 2 Last day of the month ,2 Month and minute 28 Days and 29 God ,, So we need and 4 Remainder ,
year_type=expr ${year} % 4
if [[ “ $year_type" == "0" ]];then // And 4 Take remainder as 0 It's a leap year , This year's 2 The last day of the month is 29 Number ,, The remainder is not 0 It is a normal year ,2 The last day of the month is 28 Number day="29" else day="28" fi yesterday="$ {year}-02- $d a y " / / 1, 3, 5, 7, 8, 10, 12 month all yes 31 God e l i f [["$ month” == “02” || “ $m o n t h " = = " 04 " ∣ ∣ "$ month” == “06” || “ $m o n t h " = = " 08 " ∣ ∣ "$ month” == “09” || “$month” == “11” ]];then
month=expr ${month} - 1
yesterday=" ${year}-$ {month}-31"
elif [[ “ $m o n t h " = = " 05 " ∣ ∣ "$ month” == “07” || “ $m o n t h " = = " 10 " ∣ ∣ "$ month” == “12” ]];then
month=expr ${month} - 1
yesterday=" ${year}-$ {month}-30"