LeetCode 2319. Judge whether the matrix is an X matrix

1. subject

If a square matrix satisfies the following All Conditions , It is called a X matrix ：

• matrix Diagonals All elements on are No 0
• All in the matrix other The elements are 0

Give you a size of n x n A two-dimensional array of integers grid , Represents a square matrix .
If grid It's a X matrix , return true ; otherwise , return false .

Example 1：

 Input ：grid = [[2,0,0,1],[0,3,1,0],[0,5,2,0],[4,0,0,2]]
 Output ：true
 explain ： The matrix is shown in the figure above .
X  The matrix should satisfy ： Green elements （ On the diagonal ） Are not  0 , Red elements are  0 .
 therefore ,grid  It's a  X  matrix .

Example 2：

 Input ：grid = [[5,7,0],[0,3,1],[0,5,0]]
 Output ：false
 explain ： The matrix is shown in the figure above .
X  The matrix should satisfy ： Green elements （ On the diagonal ） Are not  0 , Red elements are  0 .
 therefore ,grid  Is not a  X  matrix .
 
 Tips ：
n == grid.length == grid[i].length
3 <= n <= 100
0 <= grid[i][j] <= 10^5

source ： Power button （LeetCode）
link ：https://leetcode.cn/problems/check-if-matrix-is-x-matrix
Copyright belongs to the network . For commercial reprint, please contact the official authority , Non-commercial reprint please indicate the source .

2. Problem solving

• simulation

class Solution:
    def checkXMatrix(self, grid: List[List[int]]) -> bool:
        for i in range(len(grid)):
            for j in range(len(grid)):
                if i==j or i+j==len(grid)-1:
                    if grid[i][j]==0:
                        return False
                elif grid[i][j] != 0:
                    return False
        return True

48 ms 15.6 MB Python3

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