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[code hoof set novice village question 600] operator / type conversion in different operation sequences

2022-07-19 13:38:00 【Sandm *】

Topic link ：

Code shoe set (matiji.net)

Their thinking ：

For the calculation formula given in the topic ：

The trap involves operators / Characteristics of ,

That is, it is required that at least one side of both sides is of floating-point type ,

For the whole expression （a * x + (a+x) / (4a)） 

Because the whole has braces ,

therefore 1.0 / 2 The result of the floating-point type obtained will not be multiplied by it first ,

Instead, the program first calculates the result in braces ,

If this is not the case / When the value type on both sides changes , Then the calculation will be wrong

This is also one of the traps

 

Reference code ：

#include<bits/stdc++.h> 

using namespace std;

int main( )
{
    int x = 0,a = 0;
    //char str = '0';
    //cin >> x >> a;
    scanf("%d %d",&x,&a);
    float end = 0;
    end = (1.0/2.0)*(a*x+(a+x)/(4.0*a));
    printf("%.2f",end);// Don't forget  % 

    return 0;
}

Don't forget the % 

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