C language specifies how many days to display from the date

#include <stdio.h>
#include <stdlib.h>


const char buf_date[2][13]={
    
	{
    0,31,28,31,30,31,30,31,31,30,31,30,31},
	{
    0,31,29,31,30,31,30,31,31,30,31,30,31}};
		
static int leap_year(int year)
{
    
	if((0 == year%4 && 0 != year%100) || 0 ==  year%400)
		return 1;
	else 
		return 0;
}

static int date_find(int year, int month, int day, int n)
{
    
	int i, k, leap;
	
	
	for (i = 0; i < n; i++, day++) {
    		
		
		leap = leap_year(year);
	        if (day > buf_date[leap][month]) {
    
	        	printf("%04d %02d %02d full \n",year,month,day);	
        		day = 1;
			if(12 == month) {
    
				month = 1;
				year++;
			} else			
				month++;			
		}
        	
		printf("---------%04d %02d %02d i %d\n",year,month,day, i);	
	}
	return 0;
}
int main()
{
    
	date_find(2015, 1, 1, 1000);
}