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Test content in the first week

Programming

Test content in the first week

Programming

pro week_one
  print, ' subject 1:'
  a = findgen(4, 6)  ;  Create a 4 Column 6 Index matrix of rows （ The type is float）
  b = 3  ;  Create a value of 3 Of int Type variable 
  c = [3]  ;  Create a single element （ The value is 3） One dimension of int Type of the array 
  d = [9, 3, 1]  ;  Create a one-dimensional with three elements int Type of the array 
 
  ;  Start calculating 
  print, a[3, 4]  ;  Output numerical values in three columns and four rows 
  print, a[15]  ;  Output No 15 The value of （ Subscript from 0 Starting number ）
  print, a + b  ; +  Here is the addition of the elements of the two matrices ,  What is returned is a matrix form 
  print, a[1, 1] + b  ;  matrix a pass the civil examinations 1 Column number 1 1 That's ok （ Subscript from 0 Start ） Values and variables of b The value of the combined 
  print, a + c  ;  Because of the matrix a Is a two-dimensional array ,  and c It's a one-dimensional array ,  So generally, when adding, it returns a one-dimensional array 
  print, a + d  ;  This addition is similar 
  
  
  print, ' subject 2:'
  ;  Create a general array 
  a = [[3, 9, 10], [2, 7, 5], [4, 1, 6]]
  b = [[7, 10, 2], [5, 8, 9], [3, 1, 6]]
  ;  Array addition 、 Multiply ————》+、* That is, the elements of the array are added correspondingly 、 Multiply to return a new array 
  print, a + b
  print, a * b
  
  
  print, ' subject 3( difficult ):'
  ;  Create a general array 
  a = [[0, 5, 3], [4, 0, 2], [0, 7, 8]]
  b = [[0, 0, 1], [9, 7, 4], [1, 0, 2]]
  ;  Retain a Greater than 3 Result ,  All other elements are set to 0
  print, (a gt 3) * a
  
  ;  Retain b Medium greater than or equal to 4 Result ,  The rest of the elements are set to 9
  print, (b le 4) * b + (b gt 4) * 9
  
  ;  Calculation a and b The average of 
  print, (a + b) / 2.0  ;  Be careful , int and int Divide the type data to get int type , There will be a loss of precision ————》 There will be 2 Turn into 2.0 You can avoid 
  
  ;  Calculation a and b The average of , 0 Values are not included in the calculation （ Such as 5  and  0 The average value of is still 5）
  c = (a ne 0) + (b ne 0)  ;  Only the corresponding two are not 0 So the divisor is 2,  If only one of them is 0, So the divisor is 1,  If both are 0, So the divisor is 0
  ;  print, (c le 1) + (c eq 2) * 2.0
  print, (a + b) / ((c le 1) + (c eq 2) * 2.0)  ;  Here to c The purpose of further processing is to avoid the divisor being 0 The situation of 
  
end

The following is the result of the compilation run ：

IDL> week_one
% Compiled module: WEEK_ONE.
 subject 1:
      19.0000
      15.0000
      3.00000      4.00000      5.00000      6.00000
      7.00000      8.00000      9.00000      10.0000
      11.0000      12.0000      13.0000      14.0000
      15.0000      16.0000      17.0000      18.0000
      19.0000      20.0000      21.0000      22.0000
      23.0000      24.0000      25.0000      26.0000
      8.00000
      3.00000
      9.00000      4.00000      3.00000
 subject 2:
      10      19      12
       7      15      14
       7       2      12
      21      90      20
      10      56      45
      12       1      36
 subject 3( difficult ):
       0       5       0
       4       0       0
       0       7       8
       0       0       1
       9       9       4
       1       0       2
     0.000000      2.50000      2.00000
      6.50000      3.50000      3.00000
     0.500000      3.50000      5.00000
     0.000000      5.00000      2.00000
      6.50000      7.00000      3.00000
      1.00000      7.00000      5.00000
IDL> 

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Too few words , There are a few ugly words here , thank you .

IDL> week_one
% Compiled module: WEEK_ONE.
subject 1:
      19.0000
      15.0000
      3.00000      4.00000      5.00000      6.00000
      7.00000      8.00000      9.00000      10.0000
      11.0000      12.0000      13.0000      14.0000
      15.0000      16.0000      17.0000      18.0000
      19.0000      20.0000      21.0000      22.0000
      23.0000      24.0000      25.0000      26.0000
      8.00000
      3.00000
      9.00000      4.00000      3.00000
subject 2:
      10      19      12
       7      15      14
       7       2      12
      21      90      20
      10      56      45
      12       1      36
subject 3( difficult ):
       0       5       0
       4       0       0
       0       7       8
       0       0       1
       9       9       4
       1       0       2
     0.000000      2.50000      2.00000
      6.50000      3.50000      3.00000
     0.500000      3.50000      5.00000
     0.000000      5.00000      2.00000
      6.50000      7.00000      3.00000
      1.00000      7.00000      5.00000
IDL>