Mathf.Abs

这个函数需要提供2个数，然后返回他们差的绝对值

Mathf.Lerp

这个函数需要提供3个参数，第3个参数范围为0~1，能返回一个数，比如
（a,b,c）返回的数为a+(b-a)*c
那么依据这两个函数可以实现想要的效果,代码如下:

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class Followcamera : MonoBehaviour
{
    
    private Transform player;

    private float xMargin = 0.4f;
    private float yMargin = 0.4f;
    private float xSmooth = 5f;
    private float ySmooth = 5f;
    public Vector2 maxXAndY ;
    public Vector2 minXAndY ;

    void Start()
    {
    
        player = GameObject.FindGameObjectWithTag("Player").transform;
    }
    bool CheckXMargin() {
    
        return Mathf.Abs(transform.position.x - player.position.x) > xMargin;
    }
    bool CheckYMargin() {
    
        return Mathf.Abs(transform.position.y - player.position.y) > yMargin;
    }
    void Trackplayer() {
     
        float targetX=transform.position.x;
        float targetY=transform.position.y;
        Debug.Log(Time.deltaTime);
        if (CheckXMargin()) {
    
            targetX = Mathf.Lerp(transform.position.x,player.position.x,xSmooth*Time.deltaTime);
        }
        if (CheckYMargin()) {
    
            targetY = Mathf.Lerp(transform.position.y, player.position.y, ySmooth*Time.deltaTime );
        }
        transform.position = new Vector3(targetX,targetY,transform.position.z);
    }
    void FixedUpdate()
    {
    
        Debug.Log(Mathf.Lerp(9.0F, 1.0F, 0.1F));
        Trackplayer();
    }
}