WPF 3D application building (Foundation)

1 Create project

Choose to create WPF application
 

Give the program a cool name , Choose a cool location ：
 

Choose .NET6
 

2 Configuration items

from nuget.org Installation on AnyCAD Rapid SDK 2022.
 

3 Design interface

• First introduce the assembly ：

• xmlns:anycad="clr-namespace:AnyCAD.WPF;assembly=AnyCAD.WPF.NET6"

• Design layout

Leave a place for the three-dimensional interface , Classic left and right windows . The right side is used to display three-dimensional content . complete xaml as follows ：

<Window x:Class="WpfApp1.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:WpfApp1"
        xmlns:anycad="clr-namespace:AnyCAD.WPF;assembly=AnyCAD.WPF.NET6"
        mc:Ignorable="d"
        Title="MainWindow" Height="450" Width="800">
    <Grid>
        <Grid.ColumnDefinitions>
            <ColumnDefinition MinWidth="100" Width="0.3*"/>
            <ColumnDefinition/>
        </Grid.ColumnDefinitions>
        <anycad:RenderControl Grid.Column="1" x:Name="mRenderCtrl"/>
    </Grid>
</Window>

Run it ：
 

5 According to the model

• Add one more ViewerReady event
  

<anycad:RenderControl Grid.Column="1" x:Name="mRenderCtrl" ViewerReady="mRenderCtrl_ViewerReady"/>

• stay mRenderCtrl_ViewerReady Create a ball in

 private void mRenderCtrl_ViewerReady()
        {
            var shape = ShapeBuilder.MakeSphere(new GPnt(0, 0, 0), 100);
            mRenderCtrl.ShowShape(shape, ColorTable.AliceBlue);
        }

You cannot operate the 3D control until the initialization of the control is completed

Run it again ：
 

6 Release resources

In debug mode , When the program exits, it is in the output window , You may find such a mistake ：

1. Program “[57196] WpfApp1.exe” Exited , The return value is 3221225477 (0xc0000005) 'Access violation'.

This is because AnyCAD Rapid SDK Not releasing resources correctly . To ensure that 3D control resources can be released correctly , The program can get the normal return value , Just add it like this Startup and Exit news ：

<Application x:Class="WpfApp1.App"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             xmlns:local="clr-namespace:WpfApp1"
             StartupUri="MainWindow.xaml" Exit="Application_Exit" Startup="Application_Startup">
    <Application.Resources>
    </Application.Resources>
</Application>

Code changes ：

  public partial class App : Application
    {
        private void Application_Startup(object sender, StartupEventArgs e)
        {
            AnyCAD.Foundation.GlobalInstance.Initialize();
        }
        private void Application_Exit(object sender, ExitEventArgs e)
        {
            AnyCAD.Foundation.GlobalInstance.Destroy();
        }
    }