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3438. Number system conversion

2022-07-19 14:55:00 【Ray. C.L】

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Ideas ： take a Hexadecimal number number Turn into 10 Base number （ Qin Jiushao ）, And then divide by short to b Base number

Code ：

#include <iostream>
#include <cstring>
#include <algorithm>

using namespace std;

char itoc(int x){
    
    if(x < 10) return '0' + x;
    return 'A' + x - 10;
}

int ctoi(char x){
    
    if(x <= '9') return x - '0';
    if(x <= 'Z') return x - 'A' + 10;
    return x - 'a' + 10;
}
int main()
{
    
    int n, a, b;
    string number;
    
    cin >> a >> number >> b;
    
    n = 0;
    for(auto c : number) n = n * a + ctoi(c);
    string res;
    while(n) res += itoc(n % b) , n /= b;
    
    reverse(res.begin(), res.end());
    cout << res << endl;
    
    
    return 0;
}
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本文为[Ray. C.L]所创，转载请带上原文链接，感谢
https://yzsam.com/2022/200/202207172149597563.html

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